3[2x-4]=6[x-2]

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Solution for 3[2x-4]=6[x-2] equation:


Simplifying
3[2x + -4] = 6[x + -2]

Reorder the terms:
3[-4 + 2x] = 6[x + -2]
[-4 * 3 + 2x * 3] = 6[x + -2]
[-12 + 6x] = 6[x + -2]

Reorder the terms:
-12 + 6x = 6[-2 + x]
-12 + 6x = [-2 * 6 + x * 6]
-12 + 6x = [-12 + 6x]

Add '12' to each side of the equation.
-12 + 12 + 6x = -12 + 12 + 6x

Combine like terms: -12 + 12 = 0
0 + 6x = -12 + 12 + 6x
6x = -12 + 12 + 6x

Combine like terms: -12 + 12 = 0
6x = 0 + 6x
6x = 6x

Add '-6x' to each side of the equation.
6x + -6x = 6x + -6x

Combine like terms: 6x + -6x = 0
0 = 6x + -6x

Combine like terms: 6x + -6x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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